The structure of the compound whose IUPAC nam | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the structure of $3-$ethyl$-2-$hydroxy$-4-$methylhex$-3-$en$-5-$ynoic acid,we follow these steps:
$1$. The parent chain is a hexenoi

Vedclass · Accepted Answer

Vedclass · Answer

(C) To determine the structure of $3-$ethyl$-2-$hydroxy$-4-$methylhex$-3-$en$-5-$ynoic acid,we follow these steps:
$1$. The parent chain is a hexenoic acid,meaning it has $6$ carbon atoms with a carboxylic acid group at $C-1$.
$2$. The suffix $-3-$en$-5-$ynoic acid indicates a double bond at position $3$ and a triple bond at position $5$.
$3$. Substituents are an ethyl group at position $3$,a hydroxy group at position $2$,and a methyl group at position $4$.
$4$. Constructing the chain: $C1(COOH)-C2(OH)-C3(Et)=C4(Me)-C5\#C6$.
$5$. Comparing this with the given options,the structure corresponds to the one shown in the solution image.

The structure of the compound whose $IUPAC$ name is $3-$ethyl$-2-$hydroxy$-4-$methylhex$-3-$en$-5-$ynoic acid is:

Similar Questions

The correct $IUPAC$ name of the compound $CH_3-CH_2-C(=O)-CH(CN)-CHO$ is:

What is the $IUPAC$ name of the compound $Cl-C(=O)-OC_2H_5$?

The $IUPAC$ name of the given structure is:
$HOOC-CH_2-C(OH)(COOH)-CH_2-COOH$

Write the $IUPAC$ name of the following compound:
$OHC-CH_2-CH(CHO)-CHO$

The $IUPAC$ name for the following compound is

Vedclass Test Series

Exam Paper Generator

Online Exam Module