Successive discounts of 10 %,20 %,and 30 % ar | vedclass

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Question

(B) Let the marked price be $100$.After a $10 \%$ discount,the price becomes $100 - 10 = 90$.After a $20 \%$ discount on $90$,the price becomes $90 -

Vedclass · Accepted Answer

$49.6$

Vedclass · Answer

(B) Let the marked price be $100$.After a $10 \%$ discount,the price becomes $100 - 10 = 90$.After a $20 \%$ discount on $90$,the price becomes $90 - (0.20 	imes 90) = 90 - 18 = 72$.After a $30 \%$ discount on $72$,the price becomes $72 - (0.30 	imes 72) = 72 - 21.6 = 50.4$.The total discount is $100 - 50.4 = 49.6 \%$.Alternatively,using the formula for two successive discounts $a$ and $b$: $D = a + b - (ab/100)$.For $10 \%$ and $20 \%$: $10 + 20 - (10 	imes 20 / 100) = 30 - 2 = 28 \%$.For $28 \%$ and $30 \%$: $28 + 30 - (28 	imes 30 / 100) = 58 - 8.4 = 49.6 \%$.

Successive discounts of $10 \%$,$20 \%$,and $30 \%$ are equivalent to a single discount of (in $\%$):

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