Sucrose has molecular formula C_{12}H_{22}O_{ | vedclass

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(C) The molar mass of sucrose $(C_{12}H_{22}O_{11})$ is $(12 	imes 12) + (22 	imes 1) + (11 	imes 16) = 144 + 22 + 176 = 342 \ g/mol$. Number of mo

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$1.2$

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(C) The molar mass of sucrose $(C_{12}H_{22}O_{11})$ is $(12 	imes 12) + (22 	imes 1) + (11 	imes 16) = 144 + 22 + 176 = 342 \ g/mol$. Number of moles of sucrose = $\frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{34.2 \ g}{342 \ g/mol} = 0.1 \ mol$. Since $1 \ mol$ of $C_{12}H_{22}O_{11}$ contains $12 \ mol$ of carbon atoms,Number of moles of carbon atoms = $12 	imes 0.1 \ mol = 1.2 \ mol$.

Sucrose has molecular formula $C_{12}H_{22}O_{11}$. How many moles of carbon atoms are present in its $34.2 \ g$ sample?

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