Suitable conditions to prepare hexachlorobenz | vedclass

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Question

(D) The preparation of hexachlorobenzene $(C_6Cl_6)$ from benzene $(C_6H_6)$ involves the electrophilic substitution of all six hydrogen atoms of the

Vedclass · Accepted Answer

$Cl_2$ (excess),$UV$ light,high temperature

Vedclass · Answer

(D) The preparation of hexachlorobenzene $(C_6Cl_6)$ from benzene $(C_6H_6)$ involves the electrophilic substitution of all six hydrogen atoms of the benzene ring with chlorine atoms. This is achieved by reacting benzene with excess chlorine in the presence of a Lewis acid catalyst like anhydrous $FeCl_3$ or $AlCl_3$ in the dark. Note: The reaction shown in the image provided is the free radical addition of chlorine to benzene to form benzene hexachloride ($C_6H_6Cl_6$,also known as gammaxene or lindane),which occurs under $UV$ light. Hexachlorobenzene $(C_6Cl_6)$ is a substitution product,not an addition product. Given the options provided,none correctly describe the substitution process for $C_6Cl_6$,but option $D$ describes the addition reaction shown in the image.

Suitable conditions to prepare hexachlorobenzene $(C_6Cl_6)$ from benzene $(C_6H_6)$ is/are:

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