The sum of the absolute deviations is minimum when taken with respect to:

If $\text{Mean} = x(3 \times \text{Median} - \text{Mode})$,then what is the value of $x$?

If in a frequency distribution,the mean and median are $21$ and $22$ respectively,then its mode is approximately

Find the mode of the given frequency distribution.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
$f_i$	$2$	$18$	$30$	$45$	$35$	$20$	$6$	$3$

In a given frequency distribution,the respective values of mean and median are $21$ and $22$. The value of mode is

Let $a_1, a_2, \dots, a_{101}$ be a group of real numbers such that $a_i > a_{i+1}$ for all values of $i$ and the mean square deviation of the group is minimum about the number $a_{51}$. Then the mode of the group will be: