Surface tension of a soap solution is 2 times | vedclass

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Question

(A) soap bubble has two surfaces (inner and outer). Therefore,the total surface area is $A = 2 	imes (4\pi R^2) = 8\pi R^2$.Given: Surface tension $T

Vedclass · Accepted Answer

$64\pi 	imes 10^{-6} \, J$

Vedclass · Answer

(A) soap bubble has two surfaces (inner and outer). Therefore,the total surface area is $A = 2 	imes (4\pi R^2) = 8\pi R^2$.Given: Surface tension $T = 2 	imes 10^{-2} \, N/m$ and radius $R = 2 \, cm = 2 	imes 10^{-2} \, m$.The work done $W$ is equal to the surface energy,given by $W = T 	imes \Delta A$.$W = T 	imes 8\pi R^2$.Substituting the values:$W = (2 	imes 10^{-2}) 	imes 8 	imes \pi 	imes (2 	imes 10^{-2})^2$.$W = (2 	imes 10^{-2}) 	imes 8 	imes \pi 	imes (4 	imes 10^{-4})$.$W = 64\pi 	imes 10^{-6} \, J$.

Surface tension of a soap solution is $2 \times 10^{-2} \, N/m$. The work done in producing a soap bubble of radius $2 \, cm$ is:

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