Tautomerism is not exhibited by

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(D) Tautomerism requires the presence of at least one $\alpha$-hydrogen atom adjacent to a carbonyl group $(C=O)$ to allow for the migration of the hy

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$1,4-$Benzoquinone

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(D) Tautomerism requires the presence of at least one $\alpha$-hydrogen atom adjacent to a carbonyl group $(C=O)$ to allow for the migration of the hydrogen atom and the rearrangement of $\pi$-bonds.$A$. Phenylacetaldehyde enol $(C_6H_5-CH=CH-OH)$ can tautomerize to phenylacetaldehyde $(C_6H_5-CH_2-CHO)$.$B$. Cyclohexa$-2,5-$diene$-1,4-$dione has no $\alpha$-hydrogen atoms available,as all carbon atoms in the ring are either part of the carbonyl group or involved in $C=C$ double bonds.$C$. Cyclohexane$-1,2-$dione has $\alpha$-hydrogen atoms and can exhibit keto-enol tautomerism.$D$. $1,4$-Benzoquinone is structurally identical to Cyclohexa$-2,5-$diene$-1,4-$dione. It lacks $\alpha$-hydrogens and therefore cannot exhibit tautomerism. Since both $B$ and $D$ represent the same molecule,and the question asks for a compound that does not exhibit tautomerism,both are correct; however,$1,4$-benzoquinone is the standard textbook example for this property.

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