Ten capacitors are joined in parallel and charged with a battery up to a potential $V$. They are then disconnected from the battery and joined again in series. The potential of this combination will be ....... $V$.

Two capacitors of capacitance $2 \mu F$ and $4 \mu F$ respectively are connected in series. The combination is connected across a potential difference of $10 \ V$. The ratio of energies stored by the capacitors will be . . . . . . .

Three capacitors $1\,\mu F$,$2\,\mu F$,and $4\,\mu F$ are connected in series to a $10\,V$ source. The charge on the plates of the middle capacitor is:

The equivalent capacitance of three capacitors of capacitance $C_1, C_2$ and $C_3$ connected in parallel is $12$ units and their product is $C_1 \cdot C_2 \cdot C_3 = 48$. When the capacitors $C_1$ and $C_2$ are connected in parallel,the equivalent capacitance is $6$ units. Then the capacitances are:

Two batteries and two capacitors are connected as shown in the figure. The charge on the $2\,\mu F$ capacitor is.....$\mu C$.

Two capacitors of capacitance $2\ \mu F$ and $3\ \mu F$ are joined in series. The outer plate of the first capacitor is at $1000\ V$ and the outer plate of the second capacitor is earthed (grounded). The potential on the inner plates of each capacitor will be: (in $V$)