The pH value of 1.0 times 10^{-8} M HCl sol | vedclass

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(C) For a very dilute solution of a strong acid like $1.0 	imes 10^{-8} \ M \ HCl$,the concentration of $H^+$ ions contributed by the dissociation of

Vedclass · Accepted Answer

The ionization of water cannot be assumed to be negligible in comparison with this low concentration of $HCl$

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(C) For a very dilute solution of a strong acid like $1.0 	imes 10^{-8} \ M \ HCl$,the concentration of $H^+$ ions contributed by the dissociation of water $(1.0 	imes 10^{-7} \ M)$ cannot be ignored.Total $[H^+] = [H^+]_{HCl} + [H^+]_{H_2O} = 1.0 	imes 10^{-8} + 1.0 	imes 10^{-7} = 1.1 	imes 10^{-7} \ M$.Therefore,$pH = -\log(1.1 	imes 10^{-7}) \approx 6.96$,which is less than $7$ (and certainly less than $8$).

The $pH$ value of $1.0 \times 10^{-8} \ M \ HCl$ solution is less than $8$ because

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