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(B) The reaction between $NaOH$ (strong base) and $CH_3COOH$ (weak acid) produces sodium acetate $(CH_3COONa)$,which is a salt of a weak acid and a st

Vedclass · Accepted Answer

$8$

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(B) The reaction between $NaOH$ (strong base) and $CH_3COOH$ (weak acid) produces sodium acetate $(CH_3COONa)$,which is a salt of a weak acid and a strong base.$CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O$Since the salt undergoes anionic hydrolysis,the resulting solution is basic.For a salt of a weak acid and strong base,the $pH$ is given by $pH = \frac{1}{2} (pK_w + pK_a + \log C)$.Given $pK_a$ for $CH_3COOH$ is approximately $4.76$ and $pK_w = 14$,the calculated $pH$ is greater than $7$.Therefore,the $pH$ of the solution is $8$.

The $pH$ of the solution obtained on neutralization of $40 \ mL \ 0.1 \ M \ NaOH$ with $40 \ mL \ 0.1 \ M \ CH_3COOH$ is

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