The IUPAC name for the following compound is: | vedclass

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(A) $1$. Identify the principal functional group: The compound contains a carboxylic acid $(-COOH)$ group and an aldehyde $(-CHO)$ group. According to

Vedclass · Accepted Answer

$2,5-$dimethyl$-6-$oxo$-hex-3-$enoic acid

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(A) $1$. Identify the principal functional group: The compound contains a carboxylic acid $(-COOH)$ group and an aldehyde $(-CHO)$ group. According to $IUPAC$ priority rules,the carboxylic acid group has higher priority than the aldehyde group. Therefore,the parent chain must include the carbon of the $-COOH$ group,and the suffix will be $-oic \ acid$.
$2$. Number the carbon chain: Start numbering from the carboxylic acid carbon as $C-1$. The longest chain containing the principal functional group and the double bond is a $6-$carbon chain.
$3$. Identify substituents: The aldehyde group at $C-6$ is treated as a substituent and named as $oxo-$. There is a methyl group at $C-2$ and another methyl group at $C-5$.
$4$. Assemble the name: The substituents are $2,5-$dimethyl and $6-oxo$. The double bond is at $C-3$. Combining these,the name is $2,5-$dimethyl$-6-$oxo$-hex-3-$enoic acid.

The $IUPAC$ name for the following compound is:

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