The IUPAC name of the compound is CH_3-CH(CH_ | vedclass

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Question

(A) The given compound is $CH_3-CH(CH_3)-CH_2-CH_2-Cl$. To determine the $IUPAC$ name,we identify the longest carbon chain,which contains $4$ carbon a

Vedclass · Accepted Answer

$1-$chloro$-3-$methylbutane

Vedclass · Answer

(A) The given compound is $CH_3-CH(CH_3)-CH_2-CH_2-Cl$. To determine the $IUPAC$ name,we identify the longest carbon chain,which contains $4$ carbon atoms (butane). Numbering starts from the end closest to the substituent to give the lowest possible locants. Starting from the carbon attached to the chlorine atom,we assign $C-1$ to the carbon with the $-Cl$ group,$C-2$ to the next,$C-3$ to the carbon with the $-CH_3$ group,and $C-4$ to the terminal carbon. Thus,the substituent $-Cl$ is at position $1$ and the $-CH_3$ group is at position $3$. Alphabetical order is followed for naming substituents: 'chloro' comes before 'methyl'. Therefore,the correct $IUPAC$ name is $1-$chloro$-3-$methylbutane.

List-$I$ (structure)	List-$II$ ($IUPAC$ Name)
$A$. $CH_3CH_2CH(CH_2CH_3)CH_2CH(CH_3)CH_2CH_3$	$I$. $4-$Methylpent$-1-$ene
$B$. $(CH_3)_2C(C_3H_7)_2$	$II$. $3-$Ethyl$-5-$methylheptane
$C$. $CH_2=C(CH_3)CH=CHCH_3$	$III$. $4,4-$Dimethylheptane
$D$. $CH_2=CHCH_2CH(CH_3)CH_3$	$IV$. $2-$Methyl$-1,3-$pentadiene

The $IUPAC$ name of the compound is $CH_3-CH(CH_3)-CH_2-CH_2-Cl$.

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