The LCM of two numbers is 48. The numbers are | vedclass

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(C) Given that the $LCM$ of two numbers is $48$ and the ratio of the numbers is $2:3$.Let the two numbers be $2x$ and $3x$,where $x$ is a common multi

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$40$

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(C) Given that the $LCM$ of two numbers is $48$ and the ratio of the numbers is $2:3$.Let the two numbers be $2x$ and $3x$,where $x$ is a common multiplier.The $LCM$ of $2x$ and $3x$ is $2 	imes 3 	imes x = 6x$.According to the problem,$6x = 48$.Solving for $x$,we get $x = 48 / 6 = 8$.Therefore,the numbers are $2 	imes 8 = 16$ and $3 	imes 8 = 24$.The sum of the numbers is $16 + 24 = 40$.

The $LCM$ of two numbers is $48$. The numbers are in the ratio $2:3$. Find the sum of the numbers.

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