(B) The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n-1)d$.Given,$T_{20} = 40$ and $d = 2$.Substituting the values: $40 = a + (20-1)2$.$

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(B) The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n-1)d$.Given,$T_{20} = 40$ and $d = 2$.Substituting the values: $40 = a + (20-1)2$.$40 = a + 19 \times 2$.$40 = a + 38$.$a = 40 - 38 = 2$.Now,the second term $T_2 = a + d$.$T_2 = 2 + 2 = 4$.Therefore,the second term is $4$.

Class 10 Mathematics Arithmetic Progressions Mix Examples - Arithmetic Progressions

Medium

The $20^{th}$ term of an $A.P.$ is $40$ and the common difference is $2$. Then,its second term is $\ldots \ldots \ldots \ldots$

A
$2$
B
$4$
C
$6$
D
$0$

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Class 10 Questions

Class 10

Mathematics Questions

Chapter

Arithmetic Progressions

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Mix Examples - Arithmetic Progressions

Verify that each of the following is an $AP$,and then write its next three terms.
$5, \frac{14}{3}, \frac{13}{3}, 4, \ldots$

Medium

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Which of the following sequences is not an $A.P.$?

Easy

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Find the sum: $(-5) + (-8) + (-11) + \dots + (-230)$.

Medium

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Find the sum:
$4-\frac{1}{n}+4-\frac{2}{n}+4-\frac{3}{n}+\ldots$ up to $n$ terms.

Medium

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If the $n$th terms of the two $APs$: $9, 7, 5, \ldots$ and $24, 21, 18, \ldots$ are the same,find the value of $n$. Also,find that term.

Difficult

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The $20^{th}$ term of an $A.P.$ is $40$ and the common difference is $2$. Then,its second term is $\ldots \ldots \ldots \ldots$

Similar Questions

Verify that each of the following is an $AP$,and then write its next three terms.$5, \frac{14}{3}, \frac{13}{3}, 4, \ldots$

Which of the following sequences is not an $A.P.$?

Find the sum: $(-5) + (-8) + (-11) + \dots + (-230)$.

Find the sum:$4-\frac{1}{n}+4-\frac{2}{n}+4-\frac{3}{n}+\ldots$ up to $n$ terms.

If the $n$th terms of the two $APs$: $9, 7, 5, \ldots$ and $24, 21, 18, \ldots$ are the same,find the value of $n$. Also,find that term.

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Verify that each of the following is an $AP$,and then write its next three terms.
$5, \frac{14}{3}, \frac{13}{3}, 4, \ldots$

Find the sum:
$4-\frac{1}{n}+4-\frac{2}{n}+4-\frac{3}{n}+\ldots$ up to $n$ terms.