The 15^{th} term of the A.P. 1, 11, 21, 31, d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given $A.P.$ is $1, 11, 21, 31, \dots$Here,the first term $a = 1$.The common difference $d = 11 - 1 = 10$.The formula for the $n^{th}$ term of

Vedclass · Accepted Answer

$141$

Vedclass · Answer

(C) The given $A.P.$ is $1, 11, 21, 31, \dots$Here,the first term $a = 1$.The common difference $d = 11 - 1 = 10$.The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.To find the $15^{th}$ term,we substitute $n = 15$,$a = 1$,and $d = 10$ into the formula:$T_{15} = 1 + (15 - 1) 	imes 10$$T_{15} = 1 + 14 	imes 10$$T_{15} = 1 + 140$$T_{15} = 141$Therefore,the $15^{th}$ term is $141$.

The $15^{th}$ term of the $A.P.$ $1, 11, 21, 31, \dots$ is........

Similar Questions

Which term of the $AP: -2, -7, -12, \ldots$ will be $-77$? Find the sum of this $AP$ up to the term $-77$.

How many terms of the $A.P.$ $5, 8, 11, \dots$ add up to $670$?

For a given $A.P.$,the first term is $5$ and the $19^{th}$ term is $95$. Then,the sum of its $19$ terms is $\ldots \ldots \ldots \ldots$

Find the $n^{th}$ term of the $A.P. \, 6.4, 7.6, 8.8, 10, \ldots$

Find the sum of the first $25$ terms of the $A.P.$ $30, 26, 22, \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module