The pH of 0.1 , M aqueous solutions of NaCl,C | vedclass

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(B) $NaCl$ is a salt of a strong acid $(HCl)$ and a strong base $(NaOH)$,so it is neutral $(pH = 7)$.$NH_4Cl$ is a salt of a strong acid $(HCl)$ and a

Vedclass · Accepted Answer

$NH_4Cl < NaCl < CH_3COONa$

Vedclass · Answer

(B) $NaCl$ is a salt of a strong acid $(HCl)$ and a strong base $(NaOH)$,so it is neutral $(pH = 7)$.$NH_4Cl$ is a salt of a strong acid $(HCl)$ and a weak base $(NH_4OH)$,so it is acidic $(pH $CH_3COONa$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$,so it is basic $(pH > 7)$.Therefore,the increasing order of $pH$ for $0.1 \, M$ aqueous solutions is $NH_4Cl < NaCl < CH_3COONa$.

The $pH$ of $0.1 \, M$ aqueous solutions of $NaCl$,$CH_3COONa$ and $NH_4Cl$ will follow the order:

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