The P-V diagram of a monoatomic gas is a stra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a straight line passing through the origin in a $P-V$ diagram,the relationship is $P \propto V$,which means $P = kV$ or $\frac{P}{V} = 	ext{c

Vedclass · Accepted Answer

$2 R$

Vedclass · Answer

(B) For a straight line passing through the origin in a $P-V$ diagram,the relationship is $P \propto V$,which means $P = kV$ or $\frac{P}{V} = 	ext{constant}$.This can be written as $P V^{-1} = 	ext{constant}$.Comparing this with the polytropic process equation $P V^x = 	ext{constant}$,we get $x = -1$.The molar heat capacity $C$ for a polytropic process is given by $C = C_V + \frac{R}{1-x}$.For a monoatomic gas,$C_V = \frac{3}{2} R$.Substituting the values,$C = \frac{3}{2} R + \frac{R}{1 - (-1)} = \frac{3}{2} R + \frac{R}{2} = \frac{4 R}{2} = 2 R$.

The $P-V$ diagram of a monoatomic gas is a straight line passing through the origin. The molar heat capacity of the gas in this process will be:

Similar Questions

$2$ moles of a diatomic gas undergoes the process: $PT^2/V = \text{constant}$. The molar heat capacity of the gas during the process is:

The graph of pressure $(P)$ and volume $(V)$ according to $PV^n = C$,where $n = 1.4$. Identify the correct graph.

An enclosed one mole of a monoatomic gas is taken through a process $A$ to $B$ as shown in the figure. The molar heat capacity of the gas for this process is

$P_i, V_i$ and $P_f, V_f$ are initial and final pressures and volumes of a gas in a thermodynamic process respectively. If $PV^n = \text{constant}$, then the amount of work done is

The volume of $1 \; mole$ of an ideal gas with the adiabatic exponent $\gamma$ is changed according to the relation $V = \frac{b}{T}$,where $b$ is a constant. The amount of heat absorbed by the gas in the process if the temperature is increased by $\Delta T$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module