The $x$-intercept of a line passing through the points $\left(-\frac{1}{2}, 1\right)$ and $B(1, 3)$ is

If the intercept made by the line between the axes is bisected at the point $(5, 2)$,then its equation is

Reduce the following equation into slope-intercept form and find its slope and the $y$-intercept: $y=0$.

$A$ line $L$ perpendicular to the line $5x - 12y + 6 = 0$ makes a positive intercept on the $Y$-axis. If the distance from the origin to the line $L$ is $2$ units and the angle made by the perpendicular drawn from the origin to the line $L$ with the positive $X$-axis is $\theta$,then $\tan \theta + \cot \theta =$

The equation of the line passing through the points $(1, 2)$ and $(2, 5)$ is:

What is the equation of a line parallel to $ax + by + c = 0$ and passing through the point $(c, d)$?