The IUPAC name of the given organic compound | vedclass

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(C) The given compound is $HC \equiv C-CH=CH-CH=CH_2$.According to $IUPAC$ nomenclature rules,when both double and triple bonds are present,the double

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Hexa$-1,3-$dien$-5-$yne

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(C) The given compound is $HC \equiv C-CH=CH-CH=CH_2$.According to $IUPAC$ nomenclature rules,when both double and triple bonds are present,the double bond is given preference in numbering if the set of locants is the same.Numbering from the right side gives the double bonds positions $1$ and $3$,and the triple bond position $5$.Numbering from the left side gives the triple bond position $1$,and the double bonds positions $3$ and $5$.Comparing the sets of locants: $(1, 3, 5)$ vs $(1, 3, 5)$.Since the sets are identical,the double bond is given the lower locant.Therefore,the correct numbering starts from the right: $CH_2=CH-CH=CH-C \equiv CH$ is not the structure,but $CH_2=CH-CH=CH-C \equiv CH$ is the reverse of the given structure.Given structure: $HC \equiv C-CH=CH-CH=CH_2$.Numbering from right to left: $C_1=CH_2, C_2=CH, C_3=CH, C_4=CH, C_5=C, C_6=CH$.This gives the name Hexa$-1,3-$dien$-5-$yne.

The $IUPAC$ name of the given organic compound is $HC \equiv C-CH=CH-CH=CH_2$.

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