The IUPAC name for the compound CH_3-CO-CH_2- | vedclass

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(C) $1$. Identify the principal functional group. The carboxylic acid group $(-COOH)$ has higher priority than the ketone group $(>C=O)$.$2$. Number t

Vedclass · Accepted Answer

$4-$oxopentanoic acid

Vedclass · Answer

(C) $1$. Identify the principal functional group. The carboxylic acid group $(-COOH)$ has higher priority than the ketone group $(>C=O)$.$2$. Number the carbon chain starting from the carbon of the carboxylic acid group as $C-1$.$3$. The chain is $CH_3(5)-CO(4)-CH_2(3)-CH_2(2)-COOH(1)$.$4$. The ketone group is at position $4$,so it is named as an oxo substituent.$5$. The parent chain has $5$ carbons,so the root is pentane. Adding the suffix for the acid gives pentanoic acid.$6$. Combining these,the $IUPAC$ name is $4-$oxopentanoic acid.

The $IUPAC$ name for the compound $CH_3-CO-CH_2-CH_2-COOH$ is:

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