The pH value of which one of the following is | vedclass

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(C) For $0.1 \ M \ HNO_3$,$[H^+] = 0.1 \ M$,so $pH = -\log(0.1) = 1$. For $0.05 \ M \ H_2SO_4$,$[H^+] = 2 	imes 0.05 = 0.1 \ M$,so $pH = -\log(0.1) =

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$0.1 \ M \ CH_3COOH$

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(C) For $0.1 \ M \ HNO_3$,$[H^+] = 0.1 \ M$,so $pH = -\log(0.1) = 1$. For $0.05 \ M \ H_2SO_4$,$[H^+] = 2 	imes 0.05 = 0.1 \ M$,so $pH = -\log(0.1) = 1$. For $0.1 \ M \ CH_3COOH$,it is a weak acid and does not ionize completely,so $[H^+]  1$. For the mixture,$n(HCl) = 0.05 \ L 	imes 0.4 \ M = 0.02 \ mol$ and $n(NaOH) = 0.05 \ L 	imes 0.2 \ M = 0.01 \ mol$. Remaining $n(HCl) = 0.02 - 0.01 = 0.01 \ mol$ in $100 \ mL$ $(0.1 \ L)$ solution. $[H^+] = 0.01 \ mol / 0.1 \ L = 0.1 \ M$,so $pH = -\log(0.1) = 1$. Thus,$0.1 \ M \ CH_3COOH$ does not have a $pH$ of $1$.

The $pH$ value of which one of the following is not equal to $1$?

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