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(B) Given,$\Delta_0$ for the coordination complex is $1000 \ kJ \ mol^{-1}$.Energy of $t_{2g}$ orbitals,$E(t_{2g}) = -400 \ kJ \ mol^{-1}$.We know tha

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$ 600 $

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(B) Given,$\Delta_0$ for the coordination complex is $1000 \ kJ \ mol^{-1}$.Energy of $t_{2g}$ orbitals,$E(t_{2g}) = -400 \ kJ \ mol^{-1}$.We know that the crystal field splitting energy $\Delta_0$ is defined as the difference between the energies of $e_g$ and $t_{2g}$ orbitals:$\Delta_0 = E(e_g) - E(t_{2g})$Substituting the given values:$1000 = E(e_g) - (-400)$$1000 = E(e_g) + 400$$E(e_g) = 1000 - 400$$E(e_g) = 600 \ kJ \ mol^{-1}$Thus,the energy of $e_g$ orbitals is $600 \ kJ \ mol^{-1}$.Therefore,option $(B)$ is the correct answer.

List-$I$ (Electronic configuration of tetrahedral metal ion)	List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)
$A$. $d^2$	$I$. $-0.6$
$B$. $d^4$	$II$. $-0.8$
$C$. $d^6$	$III$. $-1.2$
$D$. $d^8$	$IV$. $-0.4$

The $\Delta_0$ of a coordination complex of a metal ion $(3d^1)$ is $1000 \ kJ \ mol^{-1}$. If the energy of $t_{2g}$ orbitals is $-400 \ kJ \ mol^{-1}$,the energy (in $kJ \ mol^{-1}$) of $e_g$ orbitals is

Similar Questions

Match the $LIST$-$I$ with $LIST$-$II$:

List-$I$ (Electronic configuration of tetrahedral metal ion) List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)

$A$. $d^2$ $I$. $-0.6$

$B$. $d^4$ $II$. $-0.8$

$C$. $d^6$ $III$. $-1.2$

$D$. $d^8$ $IV$. $-0.4$

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