The IUPAC name of the following compound is: | vedclass

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(B) $1$. Identify the longest carbon chain. The longest chain contains $6$ carbon atoms,so the parent alkane is hexane.$2$. Number the chain from the

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$4-$Ethyl$-2-$methylhexane

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(B) $1$. Identify the longest carbon chain. The longest chain contains $6$ carbon atoms,so the parent alkane is hexane.$2$. Number the chain from the end that gives the substituents the lowest possible locants. Numbering from left to right gives substituents at positions $2$ and $4$. Numbering from right to left gives substituents at positions $3$ and $5$. Thus,the correct numbering is from left to right.$3$. The substituents are a methyl group at position $2$ and an ethyl group at position $4$.$4$. According to $IUPAC$ rules,substituents are listed in alphabetical order. Therefore,ethyl comes before methyl.$5$. Combining these,the $IUPAC$ name is $4-$Ethyl$-2-$methylhexane.

The $IUPAC$ name of the following compound is:

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