The -NO_2 group in the following conjugated s | vedclass

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Question

(A) The $-NO_2$ group is a strong electron-withdrawing group due to both its inductive effect $(-I)$ and its resonance effect $(-R)$.In a conjugated s

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$-R$ effect

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(A) The $-NO_2$ group is a strong electron-withdrawing group due to both its inductive effect $(-I)$ and its resonance effect $(-R)$.In a conjugated system,such as nitrobenzene,the $-NO_2$ group pulls electron density away from the aromatic ring through resonance.This delocalization of $\pi$-electrons towards the $-NO_2$ group is characteristic of the $-R$ (or $-M$) effect.Therefore,the $-NO_2$ group shows the $-R$ effect.

The $-NO_2$ group in the following conjugated system shows:

Similar Questions

For the compound $R-CH=CH_2$,what is the order of the hyperconjugation effect for the group $R$,where $R$ is $CH_3-$,$CH_3CH_2-$,or $(CH_3)_2CH-$?

Represent hyperconjugation in $CH_3-CH_2^+$ and $CH_3-CH=CH_2$ by figure.

Which of the following is not explained by hyperconjugation?

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In which of the following compounds is the hyperconjugation effect not present?

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