The $FCC$ crystal contains how many atoms in each unit cell?

Consider an ionic solid $MX$ with $NaCl$ structure. Create a new unit cell $(Z)$ from the unit cell of $MX$ by following the sequential instructions given below. Ignore charge balance.
$(i)$ Remove all anions $(X)$ except the central one.
$(ii)$ Replace all face-centered cations $(M)$ with anions $(X)$.
$(iii)$ Remove all cations $(M)$ at the corners.
$(iv)$ Replace the central anion $(X)$ with a cation $(M)$.
The value of $\left(\frac{\text{number of anions}}{\text{number of cations}}\right)$ in $Z$ is . . . . .

The edge lengths of a simple cubic $(sc)$ and a face-centered cubic $(fcc)$ unit cell are equal. The ratio of the volume occupied by atoms in these two structures is .....

Calculate the volume occupied by all particles in a $bcc$ unit cell if the volume of the unit cell is $8.0 \times 10^{-23} \ cm^3$.

Explain how much portion of an atom located at $(i)$ corner and $(ii)$ body centre of a cubic unit cell is part of its neighbouring unit cell.

The ratio of cationic radius to anionic radius in an ionic crystal is greater than $0.732$. Its coordination number is