The V-i graph for a conductor makes an angle | vedclass

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(D) According to Ohm's Law,$V = iR$,which implies $R = V/i$.In a $V-i$ graph,the resistance $R$ is represented by the slope of the line with respect t

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$\cot 	heta$

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(D) According to Ohm's Law,$V = iR$,which implies $R = V/i$.In a $V-i$ graph,the resistance $R$ is represented by the slope of the line with respect to the $i$-axis.The slope of a line is defined as $	an(\phi)$,where $\phi$ is the angle the line makes with the $i$-axis.Given that the graph makes an angle $	heta$ with the $V$-axis,the angle it makes with the $i$-axis is $(90^\circ - 	heta)$.Therefore,the resistance $R = 	an(90^\circ - 	heta) = \cot 	heta$.

The $V-i$ graph for a conductor makes an angle $\theta$ with the $V$-axis. Here $V$ denotes the voltage and $i$ denotes the current. The resistance of the conductor is given by:

Similar Questions

The current in a metallic conductor is plotted against voltage at two different temperatures $T_1$ and $T_2$. Which of the following is correct?

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Reason : Ohm's law is a fundamental law.

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The variation of current $(i)$ passing through a conductor as the voltage $(V)$ applied across its ends is varied is shown in the adjoining diagram. If the resistance $(R)$ is determined at the points $A, B, C$ and $D$,we will find that

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