The $x - t$ graph shown in the figure represents:

The velocity-displacement $(v-s)$ graph shows the motion of a particle moving in a straight line. The velocity-displacement graph is a circle of radius $2 \ m$ and the center is at $(2, 0) \ m$. The value of acceleration for this particle at a point $(2-\sqrt{2}, \sqrt{2}) \ m$ will be $ms^{-2}$.

Constant acceleration means the slope of the $x-t$ graph is constant. True or False?

From the $v-t$ graph,find the total distance covered by the car in time $t = t_1 + t_2$.

If the velocity-time graph has the shape $AMB$,what would be the shape of the corresponding acceleration-time graph?

The distance travelled by a particle is related to time $t$ as $x = 4t^2$. The velocity of the particle at $t = 5 \, s$ is $......... \, ms^{-1}$.