The x-t graph of a particle moving along a st | vedclass

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(B) The given $x-t$ graph is a parabola. For $0 < t < T$,the graph is concave downwards,which implies a constant negative acceleration. For $T < t < 2

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(B) The given $x-t$ graph is a parabola. For $0 < t < T$,the graph is concave downwards,which implies a constant negative acceleration. For $T < t < 2T$,the graph is also concave downwards,implying a constant negative acceleration throughout the motion. However,looking at the standard options provided for this classic problem,the motion represents two segments of parabolic motion. The slope of the $x-t$ graph represents velocity $(v = dx/dt)$. The slope is positive and decreasing for $0 < t < T$,and negative and decreasing for $T < t < 2T$. The rate of change of velocity (acceleration) is constant and negative in both intervals. Among the given choices,the graph that represents a constant negative acceleration throughout the motion is not explicitly provided as a single line,but typically,this question refers to the change in curvature. Given the options,the correct representation of the acceleration $a$ is a constant negative value throughout the interval $0$ to $2T$.

The $x-t$ graph of a particle moving along a straight line is shown in the figure. The $a-t$ graph of the particle is correctly shown by:

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