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(A) Energy is released $(\varepsilon  >  0)$ in a nuclear reaction if the total binding energy of the products is greater than the total binding energ

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$(i)$ and $(iv)$

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(A) Energy is released $(\varepsilon  >  0)$ in a nuclear reaction if the total binding energy of the products is greater than the total binding energy of the reactants.$1$. For reaction $(i)$, $A + B 	o C + \varepsilon$: The nucleus $C$ has a higher binding energy per nucleon than $A$ and $B$. Thus, the total binding energy of the product $C$ is greater than the sum of the binding energies of $A$ and $B$. Therefore, $\varepsilon  >  0$.$2$. For reaction $(iv)$, $F 	o D + E + \varepsilon$: The nuclei $D$ and $E$ have higher binding energy per nucleon than $F$. Thus, the total binding energy of the products $D$ and $E$ is greater than the binding energy of the reactant $F$. Therefore, $\varepsilon  >  0$.Hence, $\varepsilon$ is positive in reactions $(i)$ and $(iv)$.

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