The absolute configuration of the given molec | vedclass

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(B) To determine the absolute configuration,we assign priorities to the groups attached to each chiral center using the Cahn-Ingold-Prelog $(CIP)$ rul

Vedclass · Accepted Answer

$R, R$

Vedclass · Answer

(B) To determine the absolute configuration,we assign priorities to the groups attached to each chiral center using the Cahn-Ingold-Prelog $(CIP)$ rules.For the first chiral center (left): The groups are $-OH$ $(1)$,$-COOH$ $(2)$,$-CH(OH)COOH$ $(3)$,and $-H$ $(4)$. Since $-H$ is on a dashed bond (pointing away),the sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise,which corresponds to the $R$ configuration.For the second chiral center (right): The groups are $-OH$ $(1)$,$-COOH$ $(2)$,$-CH(OH)COOH$ $(3)$,and $-H$ $(4)$. Since $-H$ is on a dashed bond (pointing away),the sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise,which corresponds to the $R$ configuration.Thus,the absolute configuration is $R, R$.

The absolute configuration of the given molecule is:

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