The absolute configurations of the following | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the absolute configuration,we use the $CIP$ (Cahn-Ingold-Prelog) priority rules.For the first compound:The priorities are: $1: -CH_2S

Vedclass · Accepted Answer

$S$ and $R$

Vedclass · Answer

(D) To determine the absolute configuration,we use the $CIP$ (Cahn-Ingold-Prelog) priority rules.For the first compound:The priorities are: $1: -CH_2SH$,$2: -CH_2OH$,$3: -CH_3$,$4: -H$.The lowest priority group $(-H)$ is on a wedge. The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ appears clockwise,but since the lowest priority group is on a wedge,the configuration is inverted to $S$.For the second compound:The priorities are: $1: -OH$,$2: -CH_2SH$,$3: -CH_3$,$4: -H$.The lowest priority group $(-H)$ is on a dash. The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ appears clockwise,which corresponds to $R$ configuration.Thus,the configurations are $S$ and $R$ respectively.

The absolute configurations of the following compounds are respectively:

Similar Questions

The correct statement$(s)$ about compounds $A$,$B$,and $C$ is/are:

Which of the following compounds is optically active?

Which of the following is most likely to show optical isomerism?

Number of optical isomers possible for $2$-chlorobutane is:

The number of optical isomers for the compound $CH_3-CH(OH)-CH(Cl)-CH_2-COOH$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module