The acidity of compounds I-IV in water follow | vedclass

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Question

(A) The acidity of compounds in water depends upon the ease with which they can lose $H^{+}$ ions.$1.$ Acetic acid $(CH_3COOH)$ is the strongest acid

Vedclass · Accepted Answer

$IV < I < III < II$

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(A) The acidity of compounds in water depends upon the ease with which they can lose $H^{+}$ ions.$1.$ Acetic acid $(CH_3COOH)$ is the strongest acid because the negative charge on the carboxylate ion (conjugate base) is delocalized over two oxygen atoms through resonance.$2.$ Phenol $(C_6H_5OH)$ is the next strongest acid because the phenoxide ion is stabilized by resonance within the benzene ring.$3.$ Ethanol $(C_2H_5OH)$ is more acidic than acetonitrile $(CH_3CN)$ because the hydrogen atom in ethanol is attached to a more electronegative oxygen atom,making the $O-H$ bond more polar.$4.$ Acetonitrile $(CH_3CN)$ is the least acidic among the given compounds as the $C-H$ bond is less polar compared to the $O-H$ bonds in the other compounds.Thus,the correct order of acidity is $IV < I < III < II$.

The acidity of compounds $I-IV$ in water follows the order:
$I.$ ethanol
$II.$ acetic acid
$III.$ phenol
$IV.$ acetonitrile

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The acidity of compounds $I-IV$ in water follows the order:$I.$ ethanol$II.$ acetic acid$III.$ phenol$IV.$ acetonitrile