The actinoids exhibit a greater number of oxidation states in general than the lanthanoids. This is because

  • A
    the $5f$ orbitals extend further from the nucleus than the $4f$ orbitals
  • B
    the $5f$ orbitals are more buried than the $4f$ orbitals
  • C
    there is a similarity between $4f$ and $5f$ orbitals in their angular part of the wave function
  • D
    the actinoids are more reactive than the lanthanoids

Explore More

Similar Questions

What is the electronic configuration of $Nd^{2+}$?

The common oxidation state of $f$-block elements is $+3$. The other stable oxidation states of $^{63}Eu$ and $^{65}Tb$ are respectively:

Find the atomic number of the element at which pairing in the $4f$ orbital starts.

The element californium belongs to the family of

Difficult
View Solution

Discuss the trends in oxidation states shown by actinoids.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo