The addition of three masses 1.6 ,g,7.32 ,g,a | vedclass

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(B) Given masses are $m_1 = 1.6 \,g$,$m_2 = 7.32 \,g$,and $m_3 = 4.238 \,g$.Summing these values: $m = 1.6 + 7.32 + 4.238 = 13.158 \,g$.According to t

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$13.2$

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(B) Given masses are $m_1 = 1.6 \,g$,$m_2 = 7.32 \,g$,and $m_3 = 4.238 \,g$.Summing these values: $m = 1.6 + 7.32 + 4.238 = 13.158 \,g$.According to the rules of significant figures for addition,the final result should be reported to the same number of decimal places as the measurement with the fewest decimal places.Here,$1.6 \,g$ has the fewest decimal places (one decimal place).Therefore,we round $13.158 \,g$ to one decimal place,which gives $13.2 \,g$.

The addition of three masses $1.6 \,g$,$7.32 \,g$,and $4.238 \,g$,expressed to the proper number of decimal places,is ....... $g$.

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