The adjoint matrix of begin{bmatrix} 3 & -3 & | vedclass

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(B) Let $A = \begin{bmatrix} 3 & -3 & 4 \ 2 & -3 & 4 \ 0 & -1 & 1 \end{bmatrix}$.The cofactor $C_{ij}$ of an element $a_{ij}$ is given by $(-1)^{i+j

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$\begin{bmatrix} 1 & -1 & 0 \ -2 & 3 & -4 \ -2 & 3 & -3 \end{bmatrix}$

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(B) Let $A = \begin{bmatrix} 3 & -3 & 4 \ 2 & -3 & 4 \ 0 & -1 & 1 \end{bmatrix}$.The cofactor $C_{ij}$ of an element $a_{ij}$ is given by $(-1)^{i+j} M_{ij}$,where $M_{ij}$ is the minor.$C_{11} = + \begin{vmatrix} -3 & 4 \ -1 & 1 \end{vmatrix} = (-3)(1) - (4)(-1) = -3 + 4 = 1$$C_{12} = - \begin{vmatrix} 2 & 4 \ 0 & 1 \end{vmatrix} = -(2 - 0) = -2$$C_{13} = + \begin{vmatrix} 2 & -3 \ 0 & -1 \end{vmatrix} = (-2 - 0) = -2$$C_{21} = - \begin{vmatrix} -3 & 4 \ -1 & 1 \end{vmatrix} = -(-3 + 4) = -1$$C_{22} = + \begin{vmatrix} 3 & 4 \ 0 & 1 \end{vmatrix} = (3 - 0) = 3$$C_{23} = - \begin{vmatrix} 3 & -3 \ 0 & -1 \end{vmatrix} = -(-3 - 0) = 3$$C_{31} = + \begin{vmatrix} -3 & 4 \ -3 & 4 \end{vmatrix} = (-12 + 12) = 0$$C_{32} = - \begin{vmatrix} 3 & 4 \ 2 & 4 \end{vmatrix} = -(12 - 8) = -4$$C_{33} = + \begin{vmatrix} 3 & -3 \ 2 & -3 \end{vmatrix} = (-9 + 6) = -3$The adjoint matrix is the transpose of the cofactor matrix:$adj(A) = \begin{bmatrix} C_{11} & C_{21} & C_{31} \ C_{12} & C_{22} & C_{32} \ C_{13} & C_{23} & C_{33} \end{bmatrix} = \begin{bmatrix} 1 & -1 & 0 \ -2 & 3 & -4 \ -2 & 3 & -3 \end{bmatrix}$.

The adjoint matrix of $\begin{bmatrix} 3 & -3 & 4 \\ 2 & -3 & 4 \\ 0 & -1 & 1 \end{bmatrix}$ is

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