The alkane that yields two isomeric monobromo | vedclass

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(D) The number of isomeric monobromo derivatives depends on the number of non-equivalent hydrogen atoms in the alkane.$1$. $CH_4$ (Methane) has only o

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Propane

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(D) The number of isomeric monobromo derivatives depends on the number of non-equivalent hydrogen atoms in the alkane.$1$. $CH_4$ (Methane) has only one type of $H$ atom,yielding $1$ derivative.$2$. $CH_3-CH_3$ (Ethane) has only one type of $H$ atom,yielding $1$ derivative.$3$. $C(CH_3)_4$ (Neopentane) has only one type of $H$ atom,yielding $1$ derivative.$4$. $CH_3-CH_2-CH_3$ (Propane) has two types of non-equivalent $H$ atoms (terminal $CH_3$ and central $CH_2$),yielding two isomeric monobromo derivatives: $1$-bromopropane $(CH_3-CH_2-CH_2Br)$ and $2$-bromopropane $(CH_3-CH(Br)-CH_3)$.

The alkane that yields two isomeric monobromo derivatives is

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