The amine that reacts with Hinsberg's reagent | vedclass

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Question

(A) Hinsberg's reagent (benzene sulfonyl chloride,$C_6H_5SO_2Cl$) is used to distinguish between primary,secondary,and tertiary amines.$1$. Primary $(

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$(CH_3)_2CH-NH-CH(CH_3)_2$

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(A) Hinsberg's reagent (benzene sulfonyl chloride,$C_6H_5SO_2Cl$) is used to distinguish between primary,secondary,and tertiary amines.$1$. Primary $(1^\circ)$ amines react to form $N$-alkylbenzene sulfonamides,which contain an acidic hydrogen on the nitrogen atom and are therefore soluble in alkali.$2$. Secondary $(2^\circ)$ amines react to form $N,N$-dialkylbenzene sulfonamides,which lack an acidic hydrogen on the nitrogen atom and are insoluble in alkali.$3$. Tertiary $(3^\circ)$ amines do not react with Hinsberg's reagent.In the given options,$(CH_3)_2CH-NH-CH(CH_3)_2$ is a secondary amine. It reacts with Hinsberg's reagent to form an $N,N$-disubstituted sulfonamide that has no acidic hydrogen,making it insoluble in alkali.

$Test/Method$	$Reagent$
$(i)$ Lucas Test	$(a)$ $C_6H_5SO_2Cl/aq. KOH$
$(ii)$ Dumas method	$(b)$ $HNO_3/AgNO_3$
$(iii)$ Kjeldahl's method	$(c)$ $CuO/CO_2$
$(iv)$ Hinsberg Test	$(d)$ Conc. $HCl$ and $ZnCl_2$
	$(e)$ $H_2SO_4$

The amine that reacts with Hinsberg's reagent to give an alkali-insoluble product is:

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Match the following:
$Test/Method$ $Reagent$
$(i)$ Lucas Test $(a)$ $C_6H_5SO_2Cl/aq. KOH$
$(ii)$ Dumas method $(b)$ $HNO_3/AgNO_3$
$(iii)$ Kjeldahl's method $(c)$ $CuO/CO_2$
$(iv)$ Hinsberg Test $(d)$ Conc. $HCl$ and $ZnCl_2$
$(e)$ $H_2SO_4$

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