The amount of $K_2Cr_2O_7$ (equivalent weight $49.04$) required to prepare $100 \ mL$ of its $0.05 \ N$ solution is ........ $g$.

  • A
    $2.94$
  • B
    $0.49$
  • C
    $1.47$
  • D
    $0.2452$

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