The amount of NaOH in g in 250,cm^3 of a 0.10 | vedclass

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(C) The molarity $(M)$ is defined as the number of moles of solute per liter of solution.$M = \frac{w}{M_m 	imes V_{(L)}}$Where $w$ is the mass of th

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$1$

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(C) The molarity $(M)$ is defined as the number of moles of solute per liter of solution.$M = \frac{w}{M_m 	imes V_{(L)}}$Where $w$ is the mass of the solute in $g$,$M_m$ is the molar mass of $NaOH$ $(40\,g/mol)$,and $V_{(L)}$ is the volume of the solution in liters.Given: $M = 0.100\,M$,$V = 250\,cm^3 = 0.250\,L$.Substituting the values:$0.100 = \frac{w}{40 	imes 0.250}$$w = 0.100 	imes 40 	imes 0.250 = 1\,g$.Thus,the correct option is $C$.

The amount of $NaOH$ in $g$ in $250\,cm^3$ of a $0.100\,M\,NaOH$ solution would be ........... $g$.

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