The amount of energy required to separate the nucleons from a nucleus is called:

In a nuclide, one $a.m.u.$ of mass is dissipated into energy to bind its nucleons. The energy equivalent of this mass is

If the mass defect of a nuclide is $3.32 \times 10^{-26} \ g$, its binding energy in $MeV$ is:

The isotopic mass of ${}_{3}^{7}Li$ is $7.016005 \ u$ and those of the $H$ atom and neutron are respectively $1.007825 \ u$ and $1.008665 \ u$. Then,the binding energy of the ${}_{3}^{7}Li$ nucleus is: (in $MeV$)

Consider the following nuclear reactions:
$_{92}^{238}M \to _{y}^{x}N + 2_{2}^{4}He$
$_{y}^{x}N \to _{B}^{A}L + 2\beta^{+}$
The number of neutrons in the element $L$ is:

In the radioactive decay,${}_{Z}^{A}X \to {}_{6}^{12}C + {}_{+1}^{0}e$,find the values of $A$ and $Z$.