The amount of work done in increasing the vol | vedclass

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(D) The energy stored in a capacitor is given by $U = \frac{1}{2} C V^2$. The work done in increasing the potential from $V_i$ to $V_f$ is $\Delta U =

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$1.67 W$

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(D) The energy stored in a capacitor is given by $U = \frac{1}{2} C V^2$. The work done in increasing the potential from $V_i$ to $V_f$ is $\Delta U = \frac{1}{2} C (V_f^2 - V_i^2)$. For the first case,$W = \frac{1}{2} C (10^2 - 5^2) = \frac{1}{2} C (100 - 25) = \frac{75}{2} C$. For the second case,$W_2 = \frac{1}{2} C (15^2 - 10^2) = \frac{1}{2} C (225 - 100) = \frac{125}{2} C$. Taking the ratio: $\frac{W_2}{W} = \frac{125/2 C}{75/2 C} = \frac{125}{75} = \frac{5}{3} \approx 1.67$. Therefore,$W_2 = 1.67 W$.

The amount of work done in increasing the voltage across the plates of a capacitor from $5 V$ to $10 V$ is $W$. The work done in increasing it from $10 V$ to $15 V$ will be

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