The amplitude of the magnetic field in an electromagnetic wave propagating along the $y$-axis is $6.0 \times 10^{-7} \, T$. The maximum value of the electric field in the electromagnetic wave is:
- A$5 \times 10^{14} \, Vm^{-1}$
- B$180 \, Vm^{-1}$
- C$2 \times 10^{15} \, Vm^{-1}$
- D$6.0 \times 10^{-7} \, Vm^{-1}$
Explore More
Similar Questions
In an electromagnetic wave,the phase difference between the electric and magnetic field vectors $\vec{E}$ and $\vec{B}$ is:
Medium
View Solution$A$ plane electromagnetic wave of frequency $25 \text{ MHz}$ travels in free space along the $X$-direction. At a particular point in space and time,the magnetic field is $\overrightarrow{B} = 2.1 \times 10^{-8} \hat{k} \text{ T}$. Find the electric field $\overrightarrow{E}$ at this point.
An electromagnetic wave of frequency $3 \, GHz$ enters a dielectric medium of relative electric permittivity $2.25$ from vacuum. The wavelength of this wave in that medium will be $....... \times 10^{-2} \, cm$.
DifficultJEE MAIN 2021
View SolutionThe correct statement among the following is:
What is the dimension of $\frac{1}{\mu_0 \varepsilon_0}$? ($\mu_0 =$ magnetic permeability and $\varepsilon_0 =$ permittivity of free space)
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo