The amplitude of the magnetic field part of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The amplitude of the magnetic field of an electromagnetic wave in a vacuum is given as $B_0 = 510 \; nT = 510 	imes 10^{-9} \; T$.The speed of li

Vedclass · Accepted Answer

$153$

Vedclass · Answer

(D) The amplitude of the magnetic field of an electromagnetic wave in a vacuum is given as $B_0 = 510 \; nT = 510 	imes 10^{-9} \; T$.The speed of light in a vacuum is $c = 3 	imes 10^8 \; m/s$.The amplitude of the electric field $(E_0)$ of an electromagnetic wave is related to the amplitude of the magnetic field $(B_0)$ by the relation $E_0 = c B_0$.Substituting the given values:$E_0 = (3 	imes 10^8 \; m/s) 	imes (510 	imes 10^{-9} \; T)$$E_0 = 3 	imes 510 	imes 10^{-1} \; N/C$$E_0 = 1530 	imes 10^{-1} \; N/C = 153 \; N/C$.Therefore,the amplitude of the electric field part of the wave is $153 \; N/C$.

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is $B_0 = 510 \; nT$. What is the amplitude of the electric field (in $N/C$) part of the wave?

Similar Questions

An electromagnetic wave,going through vacuum,is described by $E = E_0 \sin(kx - \omega t)$. Which of the following is independent of wavelength?

In the region far from the source,how are the oscillating electric and magnetic field vectors of an electromagnetic wave oriented?

In a plane electromagnetic wave,the average value of ....... is zero.

$A$ plane electromagnetic $(EM)$ wave is propagating along the $x$-direction. It has a wavelength of $4 \text{ mm}$. If the electric field is in the $y$-direction with a maximum magnitude of $60 \text{ Vm}^{-1}$,the equation for the magnetic field is:

The layer of the atmosphere that reflects low frequency $(LF)$ electromagnetic waves during day time only is

Vedclass Test Series

Exam Paper Generator

Online Exam Module