The amplitude of the side bands of the modulated signal, if the carrier signal and message signal amplitudes are $25 \,V$ and $5 \,V$ respectively, is (in $\,V$)

An amplitude modulated signal is given by $V(t) = 10[1 + 0.6 \cos(2.2 \times 10^4 t)] \sin(5.5 \times 10^5 t)$, where $t$ is in seconds. The sideband frequencies (in $kHz$) are: [Given $\pi = 22/7$]

$A$ modulating signal $2 \sin (6.28 \times 10^{6} t)$ is added to the carrier signal $4 \sin (12.56 \times 10^{9} t)$ for amplitude modulation. The combined signal is passed through a non-linear square law device. The output is then passed through a band pass filter. The bandwidth of the output signal of the band pass filter will be $MHz$.

For an amplitude modulated wave the minimum amplitude is $3\,V$,while the modulation index is $60\%$. The maximum amplitude of the modulated wave is $......\,V$ (in $,V$)

$A$ carrier wave is used to transmit a message signal. If the peak voltage of the modulating signal and the carrier signal are increased by $1 \%$ and $3 \%$ respectively,the modulation index is changed by (in $\%$)

$A$ carrier is simultaneously modulated by two sine waves with modulation indices of $0.4$ and $0.3$. The resultant modulation index will be