The angle between the electric lines of force | vedclass

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Question

(B) The work done in moving a charge $q$ along an equipotential surface is zero because the potential difference between any two points on the surface

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(B) The work done in moving a charge $q$ along an equipotential surface is zero because the potential difference between any two points on the surface is zero.Work done $W = \int \vec{F} \cdot d\vec{l} = q \int \vec{E} \cdot d\vec{l} = 0$.Since $q 
eq 0$ and $d\vec{l} 
eq 0$,it implies that $\vec{E} \cdot d\vec{l} = 0$.This means the electric field vector $\vec{E}$ must be perpendicular to the displacement vector $d\vec{l}$ on the equipotential surface.Therefore,the angle between the electric lines of force and the equipotential surface is $90^{\circ}$.

The angle between the electric lines of force and the equipotential surface is (in $^{\circ}$)

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