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(A) The given equation is $x^2 - 2pxy + y^2 = 0$. Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we have $a = 1$,$h = -p$,and $b = 1$.L

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$\sec^{-1} p$

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(A) The given equation is $x^2 - 2pxy + y^2 = 0$. Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we have $a = 1$,$h = -p$,and $b = 1$.Let $	heta$ be the angle between the lines. The formula for the angle is $	an 	heta = \left| \frac{2\sqrt{h^2 - ab}}{a + b} ight|$.Substituting the values,$	an 	heta = \left| \frac{2\sqrt{(-p)^2 - (1)(1)}}{1 + 1} ight| = \left| \frac{2\sqrt{p^2 - 1}}{2} ight| = \sqrt{p^2 - 1}$.Since $	an 	heta = \sqrt{p^2 - 1}$,we have $\sec^2 	heta = 1 + 	an^2 	heta = 1 + (p^2 - 1) = p^2$.Thus,$\sec 	heta = p$,which implies $	heta = \sec^{-1} p$.

The angle between the lines represented by the equation $x^2 - 2pxy + y^2 = 0$ is

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