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(B) $1$. The equation of the circle is $(x - 7)^2 + (y + 1)^2 = 25$. The center $C$ is $(7, -1)$ and the radius $r$ is $\sqrt{25} = 5$.$2$. The distan

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$90$

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(B) $1$. The equation of the circle is $(x - 7)^2 + (y + 1)^2 = 25$. The center $C$ is $(7, -1)$ and the radius $r$ is $\sqrt{25} = 5$.$2$. The distance $d$ from the origin $O(0, 0)$ to the center $C(7, -1)$ is $d = \sqrt{(7 - 0)^2 + (-1 - 0)^2} = \sqrt{49 + 1} = \sqrt{50} = 5\sqrt{2}$.$3$. Let $	heta$ be the angle between the tangents. The angle between the radius and the tangent is $90^\circ$. In the right-angled triangle formed by the origin, the center, and the point of contact, $\sin(	heta/2) = r/d$.$4$. $\sin(	heta/2) = 5 / (5\sqrt{2}) = 1/\sqrt{2}$.$5$. Therefore, $	heta/2 = 45^\circ$, which implies $	heta = 90^\circ$.

The angle between the tangents drawn from the origin $(0, 0)$ to the circle $(x - 7)^2 + (y + 1)^2 = 25$ is (in $^\circ$)

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