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(B) The expression given is a scalar triple product of the form $\overrightarrow{A} \cdot (\overrightarrow{B} 	imes \overrightarrow{A})$.By the prope

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Zero

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(B) The expression given is a scalar triple product of the form $\overrightarrow{A} \cdot (\overrightarrow{B} 	imes \overrightarrow{A})$.By the properties of the cross product,the vector $\overrightarrow{C} = (\overrightarrow{B} 	imes \overrightarrow{A})$ is perpendicular to both $\overrightarrow{A}$ and $\overrightarrow{B}$.Since $\overrightarrow{C}$ is perpendicular to $\overrightarrow{A}$,the dot product of $\overrightarrow{A}$ and $\overrightarrow{C}$ must be zero.Mathematically,$\overrightarrow{A} \cdot (\overrightarrow{B} 	imes \overrightarrow{A}) = 0$ because the vector $(\overrightarrow{B} 	imes \overrightarrow{A})$ lies in a plane perpendicular to $\overrightarrow{A}$.

The angle between the vectors $\overrightarrow{A}$ and $\overrightarrow{B}$ is $\theta$. The value of the triple product $\overrightarrow{A} \cdot (\overrightarrow{B} \times \overrightarrow{A})$ is

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