The angle of polarisation for a medium with r | vedclass

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(D) The angle of polarisation $i_{p}$ is given by Brewster's law: $\mu = 	an i_{p}$.Given $i_{p} = 60^{\circ}$,the refractive index $\mu = 	an 60^{\

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$\sin ^{-1} \frac{1}{\sqrt{3}}$

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(D) The angle of polarisation $i_{p}$ is given by Brewster's law: $\mu = 	an i_{p}$.Given $i_{p} = 60^{\circ}$,the refractive index $\mu = 	an 60^{\circ} = \sqrt{3}$.The critical angle $C$ is related to the refractive index by the formula: $\sin C = \frac{1}{\mu}$.Substituting the value of $\mu$,we get $\sin C = \frac{1}{\sqrt{3}}$.Therefore,the critical angle $C = \sin ^{-1} \left( \frac{1}{\sqrt{3}} ight)$.

The angle of polarisation for a medium with respect to air is $60^{\circ}$. The critical angle of this medium with respect to air is

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