The angle subtended at the centre of a circle | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for the angle $	heta$ subtended by an arc of length $l$ at the centre of a circle of radius $r$ is given by $	heta = \frac{l}{r}$,wh

Vedclass · Accepted Answer

$\frac{1}{3} 	ext{ radian}$

Vedclass · Answer

(C) The formula for the angle $	heta$ subtended by an arc of length $l$ at the centre of a circle of radius $r$ is given by $	heta = \frac{l}{r}$,where $	heta$ is in radians.Given,radius $(r) = 3 	ext{ m}$ and arc length $(l) = 1 	ext{ m}$.Substituting these values into the formula:$	heta = \frac{1}{3} 	ext{ radian}$.Therefore,the correct option is $C$.

The angle subtended at the centre of a circle of radius $3 \text{ m}$ by an arc of length $1 \text{ m}$ is equal to

Similar Questions

If $\cos A = m \cos B,$ then

If $\frac{1+\cos A}{1-\cos A}=\frac{m^{2}}{n^{2}}$,then $\tan A=$

$\tan 5x \tan 3x \tan 2x = ?$

$\cos \frac{\pi }{7} \cos \frac{2\pi }{7} \cos \frac{4\pi }{7} = $

$2\cos x - \cos 3x - \cos 5x = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module